The equation which is balanced and represents the correct product(s) is
- rdpiit

- Oct 23, 2020
- 1 min read
1. Li2O+2KCI→2LiCI+K2O
2.[CoCI(NH3)5]++5H+→Co2++5NH+4+CI−
3.[Mg(H2O)6]2++(EDTA)−4−→−−−−−−−ExcessNaOH [Mg(EDTA)]2++6H2O
4.CuSO4+4KCN→K2[Cu(CN)4]+K2SO4
Answer:
on adding acid, ammine complexes get destroyed.
(a) Li2O+KCI→2LiCI+K2O
This is wrong equation, since a stronger base K2O cannot be generated by a weaker base Li2O.
(b) [CoCI(NH3)5]+5H→Co2+(aq)+5NH+4+CI−
This is correct. All ammine complexes can be destroyed by adding 11th Hence on adding acid to [CoCI(NH3)5] it gets converted to Co2−(aq)+ NH−3 and CI−
(c) [Mg(H2O)6]2−+EDTA4−−→−−−ExcessOH[Mg(EDTA)]2+ +6H2O
This is wrong, since the formula of complex must be [Mg(EDTA)]2+ as EDT
(d) 4th reaction is incorrect
correct representation as
2CuSO4+10KCN→2K3[Cu(CN)4] +2K2SO4+(CN)2↑


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